Question

Choose a 3-digit number abc is
divisible by 11 as 100a+10b+c = *
9(10a+b) +(a-b+c)
-c
11(9a+b) +(a-b+c)
ac

9(10a+9b) +(a-b+c)
9(10a+b) +(a+b+c)​

Answer 1

Answer:

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