CHOOSE AN OPTION GIVINF AN EXPLAINATION IN FAVOR OF UR ANSWER
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(1) Binding energy per nucleon = total binding energy / mass number
hence
total binding energy of helium = 7*4 = 28 MeV.
total binding energy of deutron = 1.1*2 = 2.2 MeV
deutron + deutron ---------------------------> He + Q
where Q = energy = total energy of product - total energy of reactant
hence energy released = 28 - 2*2.2 = 23.6 MeV.
hence option (c) is correct.
(2) mass per unit area = 4m/πR²
mass of disc of radius R/2 = (4m/πR²)×π(R/2)² = m
formula of moment of inertia of the disc = mr²/2
apply negative mass concept
moment of inertia of remaining disc = moment of inertia of total disc - moment of inertia of removing disc
= 4mR²/2 - m(R/2)²/2
= 15mR²/8
hence option (b) is correct.
hence
total binding energy of helium = 7*4 = 28 MeV.
total binding energy of deutron = 1.1*2 = 2.2 MeV
deutron + deutron ---------------------------> He + Q
where Q = energy = total energy of product - total energy of reactant
hence energy released = 28 - 2*2.2 = 23.6 MeV.
hence option (c) is correct.
(2) mass per unit area = 4m/πR²
mass of disc of radius R/2 = (4m/πR²)×π(R/2)² = m
formula of moment of inertia of the disc = mr²/2
apply negative mass concept
moment of inertia of remaining disc = moment of inertia of total disc - moment of inertia of removing disc
= 4mR²/2 - m(R/2)²/2
= 15mR²/8
hence option (b) is correct.
prekshamehta:
Thank u so much
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(2) Mass per unit area = 4m/πR²
mass of disc of radius R/2 = (4m/πR²)×π(R/2)² = m
formula of moment of inertia of the disc = mr²/2
apply negative mass concept
moment of inertia of remaining disc = moment of inertia of total disc - moment of inertia of removing disc
= 4mR²/2 - m(R/2)²/2
= 15mR²/8
hence option (b) is correct.
mass of disc of radius R/2 = (4m/πR²)×π(R/2)² = m
formula of moment of inertia of the disc = mr²/2
apply negative mass concept
moment of inertia of remaining disc = moment of inertia of total disc - moment of inertia of removing disc
= 4mR²/2 - m(R/2)²/2
= 15mR²/8
hence option (b) is correct.
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