choose correct option .
justify your answer
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Answered by
7
The answer is given below :
When two dices are rolled simultaneously, the number of possible sample points are = 6 × 6 = 36.
Let us consider that,
K Ξ the event of getting the sum of two numbers as a square number.
So, the possible sample points are 7 in numbers and they are -
(1, 3), (2, 2), (3, 6), (3, 1), (6, 3), (4,5) and (5, 4).
Therefore, the number of probability of getting sum of the numbers as a square number,
P (K) = 7/36
So, Option (A) is is right.
Thank you for your question.
When two dices are rolled simultaneously, the number of possible sample points are = 6 × 6 = 36.
Let us consider that,
K Ξ the event of getting the sum of two numbers as a square number.
So, the possible sample points are 7 in numbers and they are -
(1, 3), (2, 2), (3, 6), (3, 1), (6, 3), (4,5) and (5, 4).
Therefore, the number of probability of getting sum of the numbers as a square number,
P (K) = 7/36
So, Option (A) is is right.
Thank you for your question.
mysticd:
what about (5 , 4 ) ,( 4 , 5)
Answered by
9
Given that number of dice rolled = 2.
Total possible outcomes n(S) = 36.
Let A be the event of getting Sum of the numbers on the dice as a square number.
n(A) = (1,3),(3,1),(2,2),(3,6),(6,3),(5,4),(4,5)
= 7.
Therefore the required probability P(A) = n(A)/n(S)
= 7/36.
Hope this helps!
Total possible outcomes n(S) = 36.
Let A be the event of getting Sum of the numbers on the dice as a square number.
n(A) = (1,3),(3,1),(2,2),(3,6),(6,3),(5,4),(4,5)
= 7.
Therefore the required probability P(A) = n(A)/n(S)
= 7/36.
Hope this helps!
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