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If n(A) = 50, n(B) = 60 and n (A∪B) = 100, the value of n (A∩B) is ,
10
-10
210
90
Answers
Answered by
2
Answer:
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Answered by
1
Step-by-step explanation:
n(AUB)= n(A) + n(B) - n(AnB)
= 100= 50 + 60 - (AnB)
= (AnB)= 110 - 100
= (AnB)= 10
Therefore n(AnB) = 10
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