Math, asked by yuvan238, 1 year ago

choose
 \sin(2 \alpha )  =   \\  \\   \sin( \alpha  ) \tan( \alpha ) \\  \cos( \alpha  )   \\  \sin( \alpha  ) \times  \sin( \alpha )  \div  \tan( \alpha )

Answers

Answered by daksh2006
3
sin(2alpha) = 2 sin(alpha) . cos(alpha)

yuvan238: cos (alpha)=sin (alpha)÷tan (alpha) so the answer is sin (alpha)×sin(alpha)÷tan(alpha)
daksh2006: but accoring to question sin(2alpha) has an identity sin(2alpha)=2sin(alpha).cos(alpha)
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