Question

Choose the correct alternative 1) The distance between the points P(-1 , 1 ) and Q(5 , -7) is _______

Answer 1

Answer:

10 units

Step-by-step explanation:

Given that there are two points in coordinate plane such that,

• P = (-1,1)
• Q = (5,-7)

To find the distance between them.

We know that,

Distance between two points having coordinate (a,b) and (c,d) is given by,

• √{(a-c)^2 + (b-d)^2}

Therefore, we will get,

=> d = √{(-1-5)^2 + (1+7)^2}

=> d = √{(-6)^2 + (8)^2}

=> d = √(36+64)

=> d = √100

=> d = 10

Hence, the required distance is 10 units.

Answer 2

Answer:

10

Step-by-step explanation:

$\sqrt{(x2-x1)^2+(y2-y1)^2}$=$\sqrt{(5-(-1))^2+((-7)-1)^2}$

=$\sqrt{(6)^2+(-8)^2}$

=$\sqrt{36+64}$

=$\sqrt{100}$

=10