Math, asked by biosafsanaaziz, 2 months ago

Choose the correct alternative:

1. Write the quadratic equation for which a+B=-11 and aß= 7 (a) x² + 11x-7-0 (b) 11r+7=0 (c)²-11x-7-0 (d) 11x 70​

Answers

Answered by Anonymous
34

Correct Question

Write The Quadratic Equation For Which α + β = -11 and αβ = 7

Solution

We have

Sum of Zeroes α + β = -11  

Product of Zeroes = αβ = 7

General Equation

x² - ( α + β )x + αβ = 0

Put the value , we get

x² -(-11)x + 7 = 0

x² + 11x + 7 = 0

Answer

x² + 11x + 7 = 0

More Information

Let equation ax² + bx + c = 0

Sum of zeroes

(α+β) = -b/a

Product of zeroes

(αβ) = c/a

Answered by Anonymous
38

{\large{\pmb{\sf{Required \: Solution...}}}}

Some knowledge about Quadratic Equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ Discriminant is given by b²-4ac

  • Discriminant tell us about there are solution of a quadratic equation as no solution, one solution and two solutions.

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

★ D > 0 then roots are real and distinct.

★ D = 0 then roots are real and equal.

★ D < 0 then roots are imaginary.

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Correct question: Write a quadratic equation for which α+β = -11 and αβ = 7

Given that:

• Sum of zeros of this quadratic equation ➝ α+β = -11

• Product of zeros of this quadratic equation ➝ αβ = 7

• General equation ➝

  • x²-(α+β)x+αβ = 0

››› x²-(α+β)x+αβ = 0

››› x² -(-11)x + 7 = 0

››› x² + 11x + 7 = 0 [ - × - = + ]

Henceforth, x² + 11x + 7 = 0 is the quadratic equation for which α+β = -11 and αβ = 7.

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