Choose the correct alternative:
1. Write the quadratic equation for which a+B=-11 and aß= 7 (a) x² + 11x-7-0 (b) 11r+7=0 (c)²-11x-7-0 (d) 11x 70
Answers
Correct Question
Write The Quadratic Equation For Which α + β = -11 and αβ = 7
Solution
We have
Sum of Zeroes α + β = -11
Product of Zeroes = αβ = 7
General Equation
x² - ( α + β )x + αβ = 0
Put the value , we get
x² -(-11)x + 7 = 0
x² + 11x + 7 = 0
Answer
x² + 11x + 7 = 0
More Information
Let equation ax² + bx + c = 0
Sum of zeroes
(α+β) = -b/a
Product of zeroes
(αβ) = c/a
Some knowledge about Quadratic Equations -
★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a
★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a
★ Discriminant is given by b²-4ac
- Discriminant tell us about there are solution of a quadratic equation as no solution, one solution and two solutions.
★ A quadratic equation have 2 roots
★ ax² + bx + c = 0 is the general form of quadratic equation
★ D > 0 then roots are real and distinct.
★ D = 0 then roots are real and equal.
★ D < 0 then roots are imaginary.
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Correct question: Write a quadratic equation for which α+β = -11 and αβ = 7
Given that:
• Sum of zeros of this quadratic equation ➝ α+β = -11
• Product of zeros of this quadratic equation ➝ αβ = 7
• General equation ➝
- x²-(α+β)x+αβ = 0
››› x²-(α+β)x+αβ = 0
››› x² -(-11)x + 7 = 0
››› x² + 11x + 7 = 0 [ - × - = + ]
Henceforth, x² + 11x + 7 = 0 is the quadratic equation for which α+β = -11 and αβ = 7.