Choose the correct alternatives. 1. A ball at rest released vertically from a height h from ground exhibits maximum velocity a) at height h/2 b) at height h/4 c) at height h/7 d) just before hitting the ground.
Answers
Answered by
1
Answer:
D)
Explanation:
I don't know explain so sorry
Answered by
1
Answer:
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Explanation:
Given that,
Height =h
Time t=
4
3T
Since, the ball is released from rest, its initial velocity is zero. When released from height h it reaches the ground in time T.
If we apply the second equation of motion
s=ut+
2
1
gt
2
h=
2
gT
2
T
2
=
g
2h
Now, we apply the same equation to calculate the height covered in time 3T/4
s=ut+
2
1
gt
2
s=g×
2
(
4
3T
)
2
s=(
32
9g
)×T
2
s=(
32
9g
)×
g
2h
s=
16
9h
Now, the distance from the ground
s=h−
16
9h
s=
16
7h
Hence, the distance from the ground is
16
7h
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