Math, asked by hkstyles9642, 1 month ago

Choose the correct ANSI
31. A father is twice as old as his son. 20 years ago the father was 12 time
than his son. What is the current age of father (in years)?
(a)
(a) 34
(b) 42
(c) 44
(d) 45
A 80

Answers

Answered by stark1997gamer
4

Answer:

(c) 44

Step-by-step explanation:

let the age of son be x therefore father's age is 2x

given 20 years ago the father was 12 times

therefore (2x - 20) = 12 (x-20)

2x-20= 12x -240

240-20=12x-2x

220=10x

x=22 ( this is son's age)

2x = 2×22= 44 (this is father's current age)

Answered by utkarshbelkhede2007
3

Answer:

44 years

Step-by-step explanation:

Let the age of son be x years and father be 2x years.

20 years back their ages were x-20 and 2x-20.

As per the given condition,

2x-20=12(x-20)

=2x–12x=20–240

=-10x =–220

= x = 220/10

x=22

2x=44

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