Question

Choose the correct answer! ​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\tt{5x-x^2-6>0}$

$\tt{\implies\,-x^2+5x-6>0}$

$\tt{\implies\,x^2-5x+6<0}$

$\tt{\implies\,x^2-3x-2x+6<0}$

$\tt{\implies\,x(x-3)-2(x-3)<0}$

$\tt{\implies\,(x-2)(x-3)<0}$

$\tt{\implies\,x\in(2,3)}$

$\tt{\implies\,2<x<3}$