Choose the correct answer in ∫√x2−8x+7dx is equal to(A)12(x−4)√x2−8x+7+9log∣x−4+√x2−8x+7∣+C(B)12(x+4)√x2−8x+7+9log∣x+4+√x2−8x+7∣+C(C)12(x−4)√x2−8x+7−3√2log∣x−4+√x2−8x+7∣+C(D)12(x−4)√x2−8x+7−92log∣x−4+√x2−8x+7∣+C
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