Question

Choose the Correct Answer:
low two
Two blocks of masses 2 kg and 4 kg are conn
by a massless string which is just taut. Now
forces 3 N and 14 N are applied on blocks. The
tension in the string is
14 N
44 kg
u = 0.4
22 kg 3N
u = 0.3
(1) 24.3 N
(2) 20 N
(3) 6N
(4) Zero​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Tension\:in\:string=0}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies m_{1} = 4 \: kg \\ \\ \implies m_{2} = 2 \: kg \\ \\ \implies \mu_{1} = 0.4 \\ \\ \implies \mu_{2} = 0.3 \\ \\ \implies f_{1} = 14 \: N\\ \\ \implies f_{2} = 3 \: N \\ \\ \underline \bold{To \: Find: } \\ \implies Tension \: in \: string = ?$

• According to given question :

$\bold{For \: fr_{1} }\\ \implies fr_{1} = \mu \times n \\ \\ \implies fr_{1} = 0.4 \times m_{1}g\\ \\ \implies fr_{1} = 0.4 \times 40 \\ \\ \bold{\implies fr_{1} = 16 \: N}\\ \\ \bold{Similarly : } \\ \implies \bold{fr_{2} = 6N}\\ \\ \bold{For \: 4 \: kg \: block : } \\ \implies Force\:applied < Friction \\ \\ \implies 14N < 16N\\ \\ \bold{So, \: there \: will \: be \: use \: of \: limiting \: friction} \\ \bold{fr_{1} \: is \: enough \: to \: take \: 4 \: kg \: block \: in \: rest} \\ \\ \bold{For \: 2 \: kg \: block : } \\ \implies Force \: applied < Friction \\ \\ \implies 3N < 6N \\ \\ \bold{So, \: here \: also \: be \: use \: of \: limiting \: friction} \\ \bold{fr_{2} \: is \: enough \: to \: take \: 2\: kg \: block \: in \: rest} \\ \\ \bold{From \: these \: two \: conclusion \: we \: conclude \: that} \\ \bold{Both \: the \: block \: will \: be \: in \: rest} \\ \bold{So, \: Tension \: in \: the \: string \: will \: be \: zero} \\ \\ \bold{\therefore Tension \: in \: string = 0}$

$\bold{Note-Friction\:always\:takes\:place\:opposite\:to\:force\:applied}$

Answer 2

Answer____

• Tension in string = 0

Step-by-step explanation :

$\bold{\implies fr_{1} = 16 \: n}\\ \\ \implies \bold{fr_{2} = 6n}\\ \\ \bold{for \: 4 \: kg \: block : } \\ \implies force < friction \\ \\ \implies 14n < 16n \\ \\ \bold{for \: 2 \: kg \: block : } \\ \implies force \: < friction \\ \\ \implies 3n < 6n \\ \\ \\ \bold{\therefore tension \: in \: string = 0}$