Choose the correct option and write it :
When
aj _5_9, then the system of equation ajx +h; y+C =0 and
az b2
C2
42x+ b2 y + C2 = 0
(a)
has unique solution.
(b) has no solution.
(c)
has two solutions.
(d) has infinitely many solutions.
Answers
Answered by
1
has infinitely many solutions.
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ʏᴏᴜ. ☺❤
Answered by
0
Answer:
If the system of equations
ax+ay-z=0
bx-y+bz=0
-x+cy+cz=0
(where a,h,c
=−1) has a non-trivial solution, then value of is independent of
1+a
1
+
1+b
1
+
1+c
1
is
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ANSWER
Given system of eqautions has non-trivial solution.
⇒
∣
∣
∣
∣
∣
∣
∣
∣
a
b
−1
a
−1
c
−1
b
c
∣
∣
∣
∣
∣
∣
∣
∣
=0
⇒a(−c−bc)−a(bc+b)−(bc−1)=0
⇒ab+bc+ca+2abc=1 -----(1)
Now,
1+a
1
+
1+b
1
+
1+c
1
=
(1+a)(1+b)(1+c)
(1+b)(1+c)+(1+a)(1+c)+(1+a)(1+b)
=
1+a+b+c+ab+bc+ca+abc
3+2a+2b+2c+ab+bc+ca
rewriting numerator using (1) gives
=
1+a+b+c+ab+bc+ca+abc
2(1+a+b+c+ab+bc+ca+abc)
=2
Hence, option A.
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