Math, asked by mdayazayaz7728, 7 months ago

Choose the correct option and write it :
When
aj _5_9, then the system of equation ajx +h; y+C =0 and
az b2
C2
42x+ b2 y + C2 = 0
(a)
has unique solution.
(b) has no solution.
(c)
has two solutions.
(d) has infinitely many solutions.​

Answers

Answered by Mrvagh151
1

has infinitely many solutions.

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ʏᴏᴜ. ☺❤

Answered by Avika125
0

Answer:

If the system of equations

ax+ay-z=0

bx-y+bz=0

-x+cy+cz=0

(where a,h,c

=−1) has a non-trivial solution, then value of is independent of

1+a

1

+

1+b

1

+

1+c

1

is

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ANSWER

Given system of eqautions has non-trivial solution.

a

b

−1

a

−1

c

−1

b

c

=0

⇒a(−c−bc)−a(bc+b)−(bc−1)=0

⇒ab+bc+ca+2abc=1 -----(1)

Now,

1+a

1

+

1+b

1

+

1+c

1

=

(1+a)(1+b)(1+c)

(1+b)(1+c)+(1+a)(1+c)+(1+a)(1+b)

=

1+a+b+c+ab+bc+ca+abc

3+2a+2b+2c+ab+bc+ca

rewriting numerator using (1) gives

=

1+a+b+c+ab+bc+ca+abc

2(1+a+b+c+ab+bc+ca+abc)

=2

Hence, option A.

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