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if log x = log 3 + 2 log 2 (374) log 16. The value of x is:
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Step-by-step explanation:
log x= log 3+ 2 log 2 - (3/4)log 16.
log x = log 3 + 2 log 2 - (3/4) log 2^4.
log x = log 3 + 2 log 2 - (3*4)/4 log 2.
log x = log 3 + 2 log 2 - 3 log 2.
log x = log 3 - log 2.
log x = log 3/2.
Therefore, by equating, x = 3/2.
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