Math, asked by murugaparasuraman197, 3 months ago

choose the correct option If the common difference of an AP is 5,then a18a13 isequal to (a) 5(b) 20 (c )30 (D)25​

Answers

Answered by shivishukla1619
0

Answer:

Answer

Correct option is

C

25

Hint: n

th

term of an A.P. is a

n

=a+(n−1)d where a is first term and d is common difference.

Given:

value of common difference ,d=5

Step 1 : Find the value of 18

th

term i.e, a

18

by replacing n with 18 in the n

th

term of the A.P

⇒a

n

=a+(n−1)d

⇒a

18

=a+(18−1)d

∴a

18

=a+17d

Step 2 : Find the value of 13

th

term i.e, a

13

by replacing n with 13 in the n

th

term of the A.P

⇒a

n

=a+(n−1)d

⇒a

13

=a+(13−1)d

∴a

13

=a+12d

Step 3 : Find the difference between a

18

and a

13

a

18

−a

13

=[a+17d]−[a+12d]

=a+17d−a−12d

=5d

=5×5

=25

Final step : Hence, a

18

−a

13

=25

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