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In a counter flow heat exchanger, hot water flows at a rate of
300kg/h and gets cooled from 90°C to 45 °C. At the same time, cold
water at 5°C enters the heat exchanger. It flows at uit rate of 300
kg/h and gets heated to 10°C. What will the LMTD of the heat
exchanger be?
Answers
Answer:
The answer is :- 300kg/h and gets cooled from 90°C to 45°C .
300kg/h and gets cooled from 90°C to 45°C
Explanation:
The logarithmic average of the temperature differential between the hot and cold feeds at either end of the double pipe exchanger is used to calculate the LMTD. The bigger the LMTD for a particular heat exchanger with constant area and heat transfer coefficient, the more heat is transmitted.
Snippets that have been highlighted
T1 = TH1 - TC1 = 100 - 30 = 700C for a co-current heat exchanger (Hot and cold fluids enter the heat exchanger at the beginning.) (Hot and cold fluids exit the heat exchanger at the opposite end.) LMTD for counter current flow = (70-40) / ln(70/40) = 30 / 0.5596 = 53.610C, according to the preceding definition.