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na box, 60% of the shapes are cubes and 40% are cones. If 10% of the cubes and 20% of the cones are blue, what is the probability
hat a blue shape selected at random is a cone?
Answers
Given : In a box, 60% of the shapes are cubes and 40% are cones. If 10% of the cubes and 20% of the cones are blue,
To Find : the probability that a blue shape selected at random is a cone
Solution:
Assume that Total shapes are = 100x
60% of the shapes are cubes = (60/100) 100x = 60x
=> cubes are 60x
Cones are 40x
10% of the cubes are blue,
=> Blue cubes = (10/100)60x = 6x
20% of the cones are blue
=> Blue cones = (20/100)40x = 8x
Total Blue shapes = 6x + 8x = 14x
Blue cones = 8x
the probability that a blue shape selected at random is a cone = 8x/14x
= 8/14
= 2/7
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Answer:
Assume that Total shapes are = 100x
60% of the shapes are cubes = = (60/100) 100x = 60x
=> cubes are 60x
Cones are 40x
10% of the cubes are blue,
(10/100)60x = 6x 20% of the cones are blue
=> Blue cubes
=> Blue cones = (20/100)40x = 8x
Total Blue shapes = 6x + 8x = 14x
Blue cones = 8x
the probability that a blue shape selected at random is a cone = 8x/14x
= 8/14
= 2/7.