Math, asked by deekshasharmads21, 19 hours ago

Choose the correct option. Pick the odd man out. Ac5 ,
Ce8
ED9
AD5

Answers

Answered by nishanth2142001
4

Answer:

ac5

Step-by-step explanation:

a is 1 and c is 3 add 4

but

ad 1 and 4 so sum 5

Answered by pulakmath007
6

SOLUTION

TO CHOOSE THE CORRECT OPTION

Pick the odd man out.

  • AC5

  • CE8

  • ED9

  • AD5

EVALUATION

We have alphabets with position as below

1A, 2B, 3C, 4D, 5E, 6F, 7G, 8H, 9I, 10J, 11K, 12L, 13M, 14N, 15O, 16P, 17Q, 18R, 19S, 20T, 21 U, 22V, 23W, 24X, 25Y and 26Z.

For AC5

Position of A + Position of C

= 1 + 3

= 4

So AC5 is wrong

For CE8

Position of C + Position of E

= 3 + 5

= 8

So CE8 is correct

For ED9

Position of E + Position of D

= 5 + 4

= 9

So ED9 is correct

For AD5

Position of A + Position of D

= 1 + 4

= 5

So AD5 is correct

FINAL ANSWER

Hence the correct option is AC5

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