Question

Choose the correct simplification of a to the 5th power times b to the 6th power all over a to the 4th power times b to the 4th power.
a9b10
ab2
1 over a times b to the 2nd power
1 over a to the 9th power times b to the 10th power

Answer 1

Answer:  $ab^2$

Step-by-step explanation:

Here, the given expression is,

a to the 5th power times b to the 6th power all over a to the 4th power times b to the 4th power.

⇒ $\frac{a^5\times b^6}{a^4\times b^4}$

⇒ $\frac{a^5}{a^4}\times \frac{b^6}{b^4}$

⇒ $a^{5-4}\times b^{6-4}$                 ( since, $\frac{a^m}{a^n}=a^{m-n}$ )

⇒ $a^1\times b^2$

⇒ $ab^2$