Physics, asked by ravitelecom, 1 month ago

Choose the correct statement/ statements:

(1)

I. Higher the value of refractive index of a medium, lower is the speed of light in that

medium.

II. Higher the optical density of a medium, lower is the speed of light in that medium.

III. Lower the value of refractive index of a medium, higher is the speed of light in that

medium.

IV. Lower the optical density of a medium, higher is the speed of light in that medium.

a) Only (ii)

b) Only (i) and (ii)

c) Only (iii) and (iv)

d) All of these​

Answers

Answered by ekta96687
0

Answer:

Refractive Index (Index of Refraction) page navigation

Refractive Index (Index of Refraction) is a value calculated from the ratio of the speed of light in a vacuum to that in a second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n' in descriptive text and mathematical equations.

Figure 1 - Refraction of Light

As presented in the figure above, a wavefront incident upon a plane surface separating two media is refracted upon entering the second medium if the incident wave is oblique to the surface. The incident angle (θ(1)) is related to the refraction angle (θ(2)) by the simple relationship known as Snell's law:

n1 × sin(θ1) = n2 × sin(θ2)

Where n represents the refractive indices of material 1 and material 2 and θ are the angles of light traveling through these materials with respect to the normal. There are several important points that can be drawn from this equation. When n(1) is greater than n(2), the angle of refraction is always larger than the angle of incidence. Alternatively when n(2) is greater than n(1) the angle of refraction is always smaller than the angle of incidence. When the two refractive indices are equal (n(1) = n(2)), then the light is passed through without refraction.

In optical microscopy, refractive index is an important variable in calculating numerical aperture, which is a measure of the light-gathering and resolving power of an objective. In most instances, the imaging medium for microscopy is air, but high-magnification objectives often employ oil or a similar liquid between the objective front lens and the specimen to improve resolution. The numerical aperture equation is given by:

NA (numerical aperture) = n × sin(θ)

where n is the refractive index of the imaging medium and θ is the angular aperture of the objective. It is obvious from the equation that increasing the refractive index by replacing the imaging medium from air (refractive index = 1.000) with a low-dispersion oil (refractive index = 1.515) dramatically increases the numerical aperture.

Interactive Tutorial - Refraction of Light

Examine how refractive index varies with the dispersion of properties of different materials.

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