Question

Choose the equation that could be used to find three consecutive integers whose sum is 36.
O a
n+ (n + 2) + (n + 4) = 36
b
n + (n + 1) + (n + 3) = 36
Ос
n + (n + 1) + (n + 2) = 36
od
n + (n - 1) + (n - 3) = 36​

Answer 1

b) n+(n+1)+(n+3)=36 the answer ♥

Answer 2

Given :  equation that could be used to find three consecutive integers whose sum is 36.

To Find : Choose correct option

n+ (n + 2) + (n + 4) = 36

n + (n + 1) + (n + 3) = 36

n + (n + 1) + (n + 2) = 36

n + (n - 1) + (n - 3) = 36​

Solution:

three consecutive integers

n , n + 1 , n + 2

=> n + (n + 1) + (n + 2) = 36   is the correct option

=> 3n = 33

=> n = 11

=> 11 , 12 & 13 are three consecutive integers whose sum is 36

n+ (n + 2) + (n + 4) = 36  => three consecutive even integers  which add upto 36

10 , 12 & 14

n + (n + 1) + (n + 3) = 36  & n + (n - 1) + (n - 3) = 36​ will not lead to integers

n + (n + 1) + (n + 2) = 36   is the correct option

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