Question

Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).

Answer 1

Answer:

find slope m (in the starting)

Answer 2

$Let \: A(x_{1},y_{1}) = (-1,2) \: and \\B(x_{2},y_{2}) = (3,1)$

$\pink { Equation \: of \: a \: line \: passes }\\\pink{ through \: the \: points \: A \: and \: B \: is }$

$\boxed{\blue{ y-y_{1} = \Big(\frac{y_{2} - y_{1}}{x_{2}-x_{1}} \Big) (x-x_{1}) }}$

$\implies y-2= \Big(\frac{ 1-2}{3-(-1)}\Big)[x -(-1)]$

$\implies y-2 = \frac{-1}{4} ( x+1)$

$\implies 4(y-2) = -(x+1)$

$\implies 4y-8 + (x+1) = 0$

$\implies x + 4y - 8 + 1 = 0$

$\implies x + 4y - 7= 0$

Therefore.,

$\red{ Required \: equation \: of \:a \:line } \\\green { \: x + 4y - 7 = 0 }$

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