choose the formula kinetic energy is equal to 1 upon 2 mv^2
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It can be proved by Newton's law of motion.....
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Kinetic energy =
_____________________
Let initial velocity = u
Let applied force = F.
Acceleration = a
Time = t
Displacement during time = s
Final velocity = v
______________________
According to the 2nd law of motion,
F = ma -------- (i) (Work done on an object W = F * s)
By using 2nd equation of motion,
S = ut + 1/2 at² (But, Initial velocity is 0)
S = 0 + 1/2 at²
Therefore,
S = 1/2 at² ------------ (ii)
Adding equation (i) and (ii)
W = ma * 1/2 at²
∴ W = 1/2 m(at)² ------------- (iii)
Now, By using first equation of Motion,
V = u + at [ (U) Initial velocity is 0]
V = 0 + at
V = at
∴ V² = at² -------------- (iv)
From equation (iii) and (iv)
W = 1/2 mv²
We know that, Work done by an object is equal to it's Kinetic Energy.
i.e. K.E = W
Therefore,
Kinetic Energy = 1/2 mv²
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