Question

choose the molecular formula of an oxide of iron in which the mass per cent of iron and oxygen are 69.9and 30.1 respectively and its​

Answer 1

Answer:

Mass % of iron = 69.9 % [Given] Mass % of oxygen = 30.1 % [Given] Fe : O = 1.25 : 1.88 Convert in simple ratio we get Fe : O = 2 : 3 The empirical formula of the iron oxide is Fe2O3.

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