Math, asked by thearone007, 5 months ago

Choose the quadratic equation having roots 2/3 and -1/2.​

Answers

Answered by shizashaheem
0

Answer:

6x²- x -2

Step-by-step explanation:

roots :

  • \frac{2}{3} ( α )
  • \frac{-1}{2} ( β )

product of zeroes → αβ = \frac{c}{a}

\frac{2}{3} x \frac{-1}{2} = \frac{c}{a}

\frac{-2}{6} = \frac{c}{a}

∴ c = -2 , a = 6

sum of zeroes → α+β  = \frac{-b}{a}

\frac{2}{3} + \frac{-1}{2} = \frac{-b}{a}

\frac{4}{6} + \frac{-3}{6} = \frac{-b}{a}

\frac{4-3}{6} = \frac{-b}{a}

\frac{1}{6} = \frac{-b}{a}

∴ -b = 1

so b = -1

a = 6

∴substituting the values in the quadratic equation, ax²+bx+c

we get → 6x²- 1x -2

6x²- x -2

hope it helped! please mark as brainliest

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