Question

choose two consecutive numbers whose product exceeds the square of the smaller number by 9​

Answer 1

Answer:

9,10

Step-by-step explanation:

let x and x+1 be the 2 consecutive no.s

given that, x(x+1) =  x²+9

              => x²+x = x²+9

              => x = 9

so, the 2 no.s are 9,9+1

ie, 9 and 10

Verification

product of 9 and 10 = 9*10 = 90   ----------- (1)

square of the smaller no. = 9*9 = 81

=> product = sqr(smaller number) + 9

hence verified