chord AB and CD of a circle intersect the circle at point E. if AE =5.6,EB=10,CE=8, find ED
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Chords AB and CD of a circle intersect inside the circle at points E. If AE = 5.6,EB=10,CE=8,find ED.
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Using theorem of intercepts of chords, we can say that
AE×BE=CE×Ed
⇒5.6×10=8×Ed
⇒dE=
8
5.6×10
⇒Ed=0.7×10=7
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