Question

Chord AB and chord CD are congruent chords of

a circle with centre O. If chord AB is at a distance

of 6 cm. from the centre then find the distance of

chord CD from the centre'​

Answer 1

Answer:

Let AB and CD are two chords of equal length of the circle with centre at O.( OP and OQ are two perpendiculars to the chords AB and CD form O)

distance of AB from O = OP and that of CD = OQ.(Now , OP is perpendicular to AB.)

P is the mid - point of AB.

(Again OQ, is perpendicular to CD.)

(Q is the mid -point of CD)

( From (1) and (2) we get)

( Now in right - angled trinagles OBP and OCQ.) BP = CQ and Hence the required distance is 4cm =》(b)