Chord AB and chord PQ are at a distance of 8cm from the center of a circle. If the length of chord AB is 12 cm then what is the length of chord PQ?
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8cm
Chords that are equidistant from the centre are equal⇔Equal chords are equidistant from the circle
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Step-by-step explanation:
Given length of chord AB = 12 cm.
Distance of chord from center = 8 cm.
OC = 8cm
AC = 12/2 = 6cm
In △OAC
OA^2 = AC^2 = OC^2
OA^2 - (6)^2 + (8)^2 = 36+64
[ OA=10 cm]
∴ Diameter of circle is 2(OA) = 20 cm.
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