Question

chord AB=chordBC=chord AC angle BAP=angle CAP.
to prove seg CB=segCQ​

Answer 1

Answer:

Step-by-step explanation:

∆ABC is equilateral triangle

Angle ACB=60

Angle BCQ=120 (linear pair)

Angle AQB=half(arc AB-arc CP) exterior angle

1/2(120-60)

=30

In ∆CBQ=C+B+Q=180

Angle CBQ=180-120-30

Angle CBQ=30

∆BCQ is isoscele triangle

Seg BC=Seg CQ

Hence prooved

Answer 2

Segment BC=Segment CQ.

Explanation:-

∆ABC is equilateral .

Angle ACB=60.

Angle BCQ=120.  

Angle AQB=1 / 2 (arcAB - arcCP) .

= 1 / 2 (120 - 60) .

Angle AQB =30 .

So,

∆CBQ=C + B + Q = 180.

Angle CBQ= 180 - 120 - 30.

Angle CBQ= 30 .

∆BCQ is isoscele triangle.

Segment BC=Segment CQ.