chord AB=chordBC=chord AC angle BAP=angle CAP.
to prove seg CB=segCQ
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Answer:
Step-by-step explanation:
∆ABC is equilateral triangle
Angle ACB=60
Angle BCQ=120 (linear pair)
Angle AQB=half(arc AB-arc CP) exterior angle
1/2(120-60)
=30
In ∆CBQ=C+B+Q=180
Angle CBQ=180-120-30
Angle CBQ=30
∆BCQ is isoscele triangle
Seg BC=Seg CQ
Hence prooved
Answered by
2
Segment BC=Segment CQ.
Explanation:-
∆ABC is equilateral .
Angle ACB=60.
Angle BCQ=120.
Angle AQB=1 / 2 (arcAB - arcCP) .
= 1 / 2 (120 - 60) .
Angle AQB =30 .
So,
∆CBQ=C + B + Q = 180.
Angle CBQ= 180 - 120 - 30.
Angle CBQ= 30 .
∆BCQ is isoscele triangle.
Segment BC=Segment CQ.
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