Question

Chord AB has the same length as the radius of the circle in which it is drawn. Endpoints of a chord AB are points of tangency of two lines in this circle. These two tangents intersect each other at point C. What is the measure of angle ACB?

Answer 1

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$let \: o \: is \: centre \: of \: the \: circle \\ ab = 2r \\ ao = bo = r \\ \\ in \: the \: triangle \: abc \\ ratio \: of \: the \: sides = ri \: isto \: r \: isto \: 2r \\ therefore \: theangles \: willbe \: 45.45.90 \\ angle \: aob = 90degrees \: since \: oa = ob = r \\ so \: angle \: acb = 45degrees \: where \: c \: is \: point \: ofjoining \: of \: two \: tangents$