Question

chord ab nd cd of a circle with centre O are congruent . if m(arc AXB = 120 then what is the m(arc CYD)​

Answer 1

Chord $AB \cong CD$ Chord

m (arc $A\times B = m$ (arc $CYD$)  (Given)

Arc corresponding to the congruant chords are congruant.

$m$ (arc $CYD$$)$  $= 120^0$.

Answer 2

m(arc CYD ) = 120 degree because arcs corresponding to the congruent chords are congruent

Step-by-step explanation:

Given:

• Chord AB and CD of a circle with centre O.
• m(arc AXB = 120)

To find: m(arcCYD)

Solution:

As per the given condition,

chord AB ≅ chord CD

m(arc A X B = m( arc CYD )

Arcs corresponding to the congruent chords are congruent

m(arc CYD ) = 120 ∘

Congruent chords:

A circle's two chords will determine equal-sized central angles if they are congruent. A circle's intercepted arcs are congruent if two of its chords are as well.

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