Chord AB subtends angle AOB equal to 60 degree at the centre o of the circle . If OA=5 cm then find the length of AB
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OA=OB(both are radii of same circle)
∠OAB=∠OBA=x(say)
In ΔAOB,
∠OBA+∠OAB+∠AOB=180°
x+x+60°=180°
2x+60°=180°⇒2x=180°-60°=120°⇒x=120/2=60°
∠OAB=∠OBA=∠AOB=60°
∴ΔAOB is equilateral
AB=OA=5cm
∴AB=5cm
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