Chord AB subtents angle AOB= 60degree at the centre of the circle. If OA =5cm find the length of AB.
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Here, OA = OB = r [radii of same circle]

⇒ ∠A = ∠B ----- (i)
In ΔOAB,
∠O + ∠A + ∠B = 180°
⇒ 60° + ∠A +∠A = 180° [using eq. (i)]
⇒ ∠A = 60°
Thus ∠O = ∠A = ∠B = 60°

⇒ ∠A = ∠B ----- (i)
In ΔOAB,
∠O + ∠A + ∠B = 180°
⇒ 60° + ∠A +∠A = 180° [using eq. (i)]
⇒ ∠A = 60°
Thus ∠O = ∠A = ∠B = 60°
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