Question

chord subtends an angle of 90°at the centre of a circle whose chord is 20 cm. Compute the area of the corresponding major segment of​

Answer 1

[HeY Mate]

Answer:

Note:

●Area of the sector = θ/360 × π × r2

●Base and height of the triangle formed will be = radius of the circle

●Area of the minor segment = Area of the sector – (Area of the triangle formed)

●Area of the major segment = area of the circle – (Area of the minor segment)

Solution:

Radius of circle(r) = 20 cm

Angle subtended = θ = 90°

Area of the sector = θ/360 × π × r^2 = 90/360 × 22/7 × 202 = 314.2 cm^2

=> Area of the triangle

= ½ × base × height = ½ × 20 × 20 = 200 cm2

=> Area of the minor segment

= 314.2 – 200 = 114.2 cm2

(Area of the circle = π × r^2)

Area of the major segment,

= π × r^2 – 114.2

= 1142 .94 cm^2

Hence, the area of the corresponding major segment of the circle = 1142 .94 cm^2

I Hope It Helps You✌️

Answer 2

Answer:

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