Question

Chords AB & CD of a circle intersect inside the circle at point E . If AE= 5.6 EB= 10, CE= 8 .Find ED ??

Answer 1

Answer:

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Explanation:

Given conditions ⇒

AE = 5.6

EB = 10

CE = 8

Now, As per as the question, chord intersects internally.

We know that if the chord intersects internally then the products of the segments of the chords are equals.

∴ AE × EB = CE × DE

⇒ 5.6 × 10 = 8 × DE

⇒ DE = 56/8

⇒ DE = 7

Therefore ED=7