Chords AB and CD intersect each other in point M .P is center of circle . Radius of circle is 13cm and PM =5cm . Find product of CM into DM
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Answer:
144
Step-by-step explanation:
Given Chords AB and CD intersect each other in point M .P is center of circle . Radius of circle is 13cm and PM =5cm . Find product of CM into DM
According to the theorem Inside a circle the product of their segments are equal when two chords intersect each other, The longest chord of a circle is diameter.
So draw a diameter in a circle passing through points P and M. The line AB is the diameter and P is the centre of circle.
Since it is diameter , AB = 2 x radius
= 2 x 13 = 26 cm
MB = PY - PM = 13 - 5 = 8
MA = PM + PA = 13 + 5 = 18
From the above theorem we have,
CM x MD = MA x MB
8 x 18 = 144
So CM x DM = 144 cm
rahulsonawane231:
Plzz show the diagram
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