Chords AB and CD of a circle intersect at E and are
perpendicular to each other. Segments AE, EB and ED
are of lengths 2 cm, 6 cm and 3 cm respectively. Then the
length of the diameter of the circle in cm is.
Answers
Answered by
2
Answer:
Given , AE = 2 cm
EB = 6 cm
ED = 3 cm
∴ AE × EB = DE × EC
⇒ EC =
2 × 6
= 4 cm.
3
∴ Diameter = √7² + 4² = √49 + 16 = √65 cm
Answered by
0
Answer:
I have a look at the moment
Similar questions