Question

Chords ab and cd of a circle intersect at right angle at the point p. If the lengths of ap, pb, cp be 2, 6, 3 respectively, then the radius of the circle is

Answer 1

answer:

$2 \sqrt{5}$

step by step instructions:

• make a circle
• construct 2 ab and cd chord intersecting at right angle at point P
• ap=2
• pb=6
• cp=3
• construct the diameter parallel to the chord ab
• join the points a o and o b respectively
• you will get a triangle
• with the help of pythagoras thaeram's hypotenuse method , find the distance