Chords AB and CD of a circle intersect each other in point M. The Centre of the circle is P. The radius of the circle is 13cm and PM=5cm.Find the product CM×DM.
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Assuming point M is the midpoint of chord CD, and M is a point of tangency to the circle M is on with radius 5, it follows that CD ⊥ PM, and two congruent right-triangles are formed. Using Pythagoras, CM = MD = 12 units, and the product of those two lengths will be 144.
Assuming point M is the midpoint of chord CD, and M is a point of tangency to the circle M is on with radius 5, it follows that CD ⊥ PM, and two congruent right-triangles are formed. Using Pythagoras, CM = MD = 12 units, and the product of those two lengths will be 144.
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two length is 144
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