chords AB and CD of a circle intersect inside the circle at point E.if AE =5.6
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AE=5.6
EB=10
CE=8
Now, As per as the question, chord intersect internally.
We know that if the chord intersects internally then the products of the segments of the chords are equals.
∴AE×EB=CE×DE
5.6×10=8×DE
DE=
8
56
DE=7
Hence, Option A is correct.
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