Question

Chords AB and CD of a circle intersect inside the circle at point E.
If AE = 5.6, EB = 10, CE = 8, find ED.
(A) 7 (B) 8 (C) 11.2
(D) 9​

Answer 1

Answer:

AE×EB=CE×DE

5.6×10=8×DE

DE=56/8

DE=7

so correct option is (A)7

Answer 2

GIVEN:- AE=5.6 , EB=10 , CE=8

TO FIND :- ED

SOLUTION:-

• Now, As per as the question, chord intersect internally.

• We know that if the chord intersects internally then the products of the segments of the chords are equals.

• ∴AE×EB=CE×DE [Theorem of internal division of chords]

• 5.6×10=8×DE

ANSWER :-

$\boxed{ ∴ ED = 7 \: units \: }$

HENCE, THE CORRECT ANSWER IS 7

$\huge\pink{\mathfrak{hope \: it \: helps \: }}$