Question

Chords AB and CD of a circle intersect inside the circle at point E. If AE = 5.6, EB = 10, CE = 8, find ED​

Answer 1

Step-by-step explanation:

Given: AB intersect CD

& AE=5.6, EB=10, CE=8

To find:DE=?

we know that if the chords intersect internally then the products of the segments of the chord are equal.

:. AE×EB=CE×ED

5.6×10=8×ED

56=8×ED

56÷8=ED

7=ED

hope it helps you!