Chords AB and CD of a circle intersect inside the circle at point E. If AE=5.6,EB =10,CE=8, find ED.Choose the correct alternative.
(A) 7
(B) 8
(C) 11.2
(D) 9
Answers
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Answer ⇒ Option (a).
Explanation ⇒
Refers to the attachment.
Given conditions ⇒
AE = 5.6
EB = 10
CE = 8
Now, As per as the question, chord intersect internally.
We know that if the chord intersects internally then the products of the segments of the chords are equals.
∴ AE × EB = CE × DE
⇒ 5.6 × 10 = 8 × DE
⇒ DE = 56/8
⇒ DE = 7
Hence, Option (a) is correct.
Hope it helps.
Explanation ⇒
Refers to the attachment.
Given conditions ⇒
AE = 5.6
EB = 10
CE = 8
Now, As per as the question, chord intersect internally.
We know that if the chord intersects internally then the products of the segments of the chords are equals.
∴ AE × EB = CE × DE
⇒ 5.6 × 10 = 8 × DE
⇒ DE = 56/8
⇒ DE = 7
Hence, Option (a) is correct.
Hope it helps.
Attachments:
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