Question

Chords AB and CD of a circle intersect inside the circle at point E. If AE= 7.2, EB=10,CE=8, find ED

Answer 1

Chords AB and CD of a circle intersect inside the circle at point E. If AE= 7.2, EB=10,CE=8, find ED.

Step by step explanation :

Refer the attachment for figure.

Given :

AE = 7.2

EB = 10

CE = 8

To find : ED

Solution :

By theorem of chords intersecting inside the circle,

AE × EB = CE × ED

Just put the given values and solve :

7.2 × 10 = 8 × ED

72 = 8 × ED

72/8 = ED

9 = ED  

Thus, The value of ED is 9.

Hence, ED = 9.

Answer 2

AE × BE = CE × ED

7.2 × 10 = 8 × ED

72 = 8 × ED

72÷8 = ED

9 = ED