Question

*Chords AB and PQ of a circle intersect inside the circle at point M. If AM = 4, BM = 12, PM = 8, find QM.*

1️⃣ 10
2️⃣ 12
3️⃣ 8
4️⃣ 6​

Answer 1

Answer:

6

Step-by-step explanation:

by intersecting chord theorem (proved by similarity)

AM X BM=PM X QM

Answer 2

Given :  Chords AB and PQ of a circle intersect inside the circle at point M  

AM = 4, BM = 12, PM = 8,

To Find : QM.

1️⃣ 10

2️⃣ 12

3️⃣ 8

4️⃣ 6​

Solution:

If two chords of a circle intersect inside a circle,

the product of the lengths of the segments of first chord at the point of intersection is equal to the product of the lengths of segments at the point of intersection   of the second chord

=> AM x BM = PM x QM

AM = 4

BM = 12

PM = 8

QM = ?

=> 4 x 12 = 8 x QM

=> 48  = 8 x QM

=> 6 = QM

QM = 6

Correct option is  4️⃣ 6​

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