Chords AB and PQ of a circle intersect inside the circle at point M. If AM=4, BM=12, PM=8, find QM
Answers
Given : Chords AB and PQ of a circle intersect inside the circle at point M
AM = 4, BM = 12, PM = 8,
To Find : QM.
1️⃣ 10
2️⃣ 12
3️⃣ 8
4️⃣ 6
Solution:
If two chords of a circle intersect inside a circle,
the product of the lengths of the segments of first chord at the point of intersection is equal to the product of the lengths of segments at the point of intersection of the second chord
=> AM x BM = PM x QM
AM = 4
BM = 12
PM = 8
QM = ?
=> 4 x 12 = 8 x QM
=> 48 = 8 x QM
=> 6 = QM
QM = 6
Correct option is 4️⃣ 6
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