Chords AC and BD intersect at E, with BD = 7 units, DE = 2 units, and AE = 4 units. What is the length of segment CE?
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Answered by
55
Answer:
Step-by-step explanation:
Given that the chords AC and BD intersect at E, with BD = 7 units, DE = 2 units, and AE = 4 units.
we have to find the length of segment CE.
BD=7 units
DE=2 units
AE=4 units
BE=BD-DE=7-2=5 units
By intersecting chord theorem which states that when two chords intersect each other inside a circle then the products of their segments are equal i.e
5/4=x/2
5*2/4=x
10/4=x
2.5=x
Hence, the length of segment CE is 2.5 units
Answered by
11
Answer:
2.5
Step-by-step explanation:
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