Question

Chords AC and DE intersect at B. If angle ABE = 108°, m(arc AE) = 95°, find m(arc DC)​

Answer 1

Step-by-step explanation:

Chords AC and DE intersect internally at point B. ∴ ∠ABE = 1/2 [m(arc AE) + m(arc DC)]

∴ 108° = 1/2 [95° + m(arc DC)]

∴ 108° × 2 = 95° + m(arc DC)

∴ 95° + m(arc DC) = 216°

∴ m(arc DC) = 216° – 95°

∴ m(arc DC) = 121°

hope its right answer

Answer 2

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Chords AC and DE intersect internally at point B. ➡∠ABE = 1/2 [m(arc AE) + m(arc DC)]

➡ 108° = 1/2 [95° + m(arc DC)]

➡ 108° × 2 = 95° + m(arc DC)

➡95° + m(arc DC) = 216°

➡ m(arc DC) = 216° – 95°

➡ m(arc DC) = 121°

hope it helps