Question

Chords equidistant from the centre of a circle are equal in length​

Answer 1

Step-by-step explanation:

Given: OM and ON are perpendicular from the centre to the chords AB and CD and OM=ON

To Prove: AB=CD

Construction: Join OA and OC

Proof: OM perpendicular AB = half AB =AM

ON perpendicular CD =half CD=CN

Consider triangle AOM and triangle CON

OA=OC

OM=ON

Angle OMA=Angle ONC =90

so triangle AOM congruent triangle CON

By RHS rule

So AM=CN

=half AB =half CD

=AB=CD

Hence proved

Answer 2

Step-by-step explanation:

1this is the correct answer this is the theoram 7 of ch 10